Synthesis and Purification of Acetylsalicylic Acid Essay Example for Free

Synthesis and Purification of Acetylsalicylic Acid EssaySynthesis and Purification of Acetylsalicylic Acid (ASA or Aspirin) Background Salicylic sharp is a hydroxybenzene as well as a carboxylic acid. It can therefore undergo two different types of esterification reactions, creating an ester either with the hydroxyl or with the acid. In the front man of acetic anhydride, acetylsalicylic acid (aspirin or ASA) is formed. Correspondingly, an excess of methanol willing form methyl salicylate, which is also an analgesic. In this experiment, we shall use the former reaction to prepare aspirin. Salicylic acid will non react significantly with acetic acid to produce aspirin.Acetic acid anhydride, however, is more reactive than acetic acid because the acetoxy group (-O2CCH3) is a much better leaving group than the OH- of acetic acid. The reaction has one complication, however, in that an esterification can occur between the phenol and acid portion of near salicylic acid molecules. Further, more molecules can bind to the remaining free substituents on these molecules to create a macromolecule, or polymer. The polymer is formed as a by-product. Acetylsalicylic acid will react with sodium bicarbonate to form a water-soluble sodium salt, whereas the polymer remains insoluble.This difference can be used to purify the aspirin product. The more or less likely impurity in the final product is salicylic acid, which can be either unconsumed reactant, or the result of hydrolysis of the aspirin product. Salicylic acid is removed during the catharsis steps as well. Salicylic acid, like most phenols, forms a highly colored conglomerate with ferric chloride, and is easily detected. Aspirin does not form the colored complex because the hydroxyl has been acetylated.Provide tabulated and experimental MPs for product. Report mass and moles for the reactant and product, and calculate yield % on a molar basis. Mechanism The mechanism is called nucleophilic acyl group substitut ion. It is similar, but not identical, to the hydrolysis on pg 802. The entering nucleophile is salicylic acid, not water. On the resulting tetrahedral intermediate, the H from salicylic acid moves to the middle O on the anhydride. Finally, the leaving group is acetic acid, not chloride. No base is involved. Provide structures of all intermediates in your lab report.